9p^2-56+12=0

Solution for 9p^2-56+12=0 equation:

9p^2-56+12=0

We add all the numbers together, and all the variables

9p^2-44=0

a = 9; b = 0; c = -44;
Δ = b2-4ac
Δ = 02-4·9·(-44)
Δ = 1584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1584}=\sqrt{144*11}=\sqrt{144}*\sqrt{11}=12\sqrt{11}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{11}}{2*9}=\frac{0-12\sqrt{11}}{18}
=-\frac{12\sqrt{11}}{18}
=-\frac{2\sqrt{11}}{3}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{11}}{2*9}=\frac{0+12\sqrt{11}}{18}
=\frac{12\sqrt{11}}{18}
=\frac{2\sqrt{11}}{3}
$